Bully's Prize Board (Parity Sweeper)
(Eingestellt am 13. Juni 2026, 07:38 Uhr von damo_89)
"Keep out of the black and in the red; nothing in this game for two in a bed"
This puzzle began life as an experiment around using parity sweepers and insisting that the circles all contain different digits. I enjoyed the shading logic, and then tried to find a suitable disambiguator. As my brain is strange, this reminded me of the prize round from Bullseye (ask your parents). Good luck!
- Normal sudoku rules apply: Place the digit 1 to 9 once each in every row, column, and 3x3 box
- Parity Sweepers: A digit in a red circle counts how many of the up to 9 surrounding cells have the same parity as the digit in the circle, including counting itself. (E.g. if a circle contained a 6, then 5 of the 8 cells that touch orthogonally or diagonally must contain an even digit, in addition to counting the 6 itself)
- Not Parity Sweepers: A digit in a black square does not count how many of the up to 9 surrounding cells have the same parity as the digit in the square, including counting itself. (E.g. if a square contained a 6, then we must not have 5 of the cells that touch orthogonally or diagonally containing an even digit)
- Extra Region: Every circle contains a different digit. Every square contains a different digit
Play on Sudokupad
Download full solution guide (PDF)
Lösungscode: Row 9
Zuletzt geändert -
Gelöst von Elliott810, Bravissimo, Briks, SKORP17, jill0100, emoney1374, blueberrypug, Gunkan, caiogi, kangaroo, tuturitu, Malakree, olliwright, GinaT86
Kommentare
am 13. Juni 2026, 09:08 Uhr von Elliott810
Brilliant puzzle! Thank you:)