Logic Masters Deutschland e.V.

Trichroma Paintomino #3

(Eingestellt am 12. März 2026, 20:36 Uhr von MaizeGator)

The third puzzle in the Trichroma Paintomino series continues to build upon the ideas introduced in #1 and #2. The “intended” difficulty is 3*, but you may find it easier, particularly if you’ve been getting familiar with the ruleset.

RULES:
  • Divide each bold-outlined region into three differently-sized sub-groups of cells. Then, assign one of three colors to each group so that each region contains exactly one group of each color.

  • A digit in a cell indicates the size of that cell’s group.

  • Sub-groups that border one another through a bold region boundary may not be the same color OR the same shape (counting rotations and reflections as the same). For example, two touching S-tetrominos in different configurations is not allowed, but an S-tetromino may touch a T-tetromino.

  • When the colors of the sub-groups for each region are placed in order from largest to smallest, any pair of bordering regions must have a different order.

A complete ruleset demonstration is available here

Solve the Example in Penpa

Lösungscode: The sizes of each cell’s sub-group row 5, left-to-right


Gelöst von Christounet, Piatato, tryote, sehringdipity, Chaossudokusplease, Calesch, Jesper, elmers, Franjo, puzzler05, zuzanina, Agent, Mr_tn, JustinTucker, josh_johnson, QuiltyAsCharged, PrimeWeasel, ... mellowrobinson, kyuquu, GaviGuy, MazzleFlush, mortaxic, cowabunghole, dogfarts, johnyzzh, Felis_Timon, misko, SFP, chenlu, webato, h5663454, Kpn, JennaStella, sfushidahardy, yttrio, Mark Sweep
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Kommentare

am 15. März 2026, 15:24 Uhr von QuiltyAsCharged
This ruleset works quite nicely. A brilliant invention!

am 13. März 2026, 19:05 Uhr von Agent
Neat!

am 13. März 2026, 13:23 Uhr von Franjo
Maybe you‘d better chosen another row for the solution code as the last (nice!) deduction didn’t use row 5? Anyway, thank you very much for creating and sharing another beautiful puzzle of this new genre.

am 12. März 2026, 22:00 Uhr von Piatato
Fun one again, thanks!

Schwierigkeit:2
Bewertung:98 %
Gelöst:42 mal
Beobachtet:1 mal
ID:000RV7

Lösung abgeben

Lösungscode:

Anmelden