Logic Masters Deutschland e.V.

Parity Fun 14

(Eingestellt am 31. Januar 2026, 11:23 Uhr von galium_odoratum)

This time I decided to create an original version and an alternate, more beginner friendly version (~0.5* easier I would guess), though both should be fairly approachable. Have fun!

Normal Sudoku rules apply.

Positive parity diagonal: Digits along the positive diagonal cannot repeat. In addition, the diagonal acts as a parity mirror: the parity of each cell (odd or even) is mirrored symmetrically across the diagonal.

Roman Numerals: Two orthogonally adjacent digits joined by a Roman numeral must sum to the value indicated by that numeral. Not all such clues are necessarily given.

Fog: Some clues are hidden by the fog and will be revealed when needed.

Play on SudokuPad (original version)
Play on SudokuPad (more beginner friendly version: less fog, one additional clue)



Try out the others of this series:
Parity Fun 1
Parity Fun 2
Parity Fun 3
Parity Fun 4
Parity Fun 5
Parity Fun 6
Parity Fun 7
Parity Fun 8
Parity Fun 9
Parity Fun 10
Parity Fun 11
Parity Fun 12
Parity Fun 13

Lösungscode: Row 6

Zuletzt geändert am 31. Januar 2026, 14:31 Uhr

Gelöst von jalebc, butch02, Gribba Bibba, Mathemagier, PippoForte, scarfdoku, SKORP17, jguer, cygne, jordanza, Freegerator, illegel, annaeinachin, jkuo7, kublai, Yoica, lianarox, sehringdipity, schnitzl, ... Julianl, sigge, olegavibe, Crul, belnovic, TroublesomeOrca, ole-1995a, JohnDoeJersey, paranoid, CrippledLamp, Kabuki73, RadchenkoAleksandr, jrn, SPOU1, Jdt112, mcs131313, kdwji, LLX, kangaroo
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Kommentare

am 1. Februar 2026, 12:46 Uhr von annaeinachin
This was quite a challange for me personally, I problably shoud have tried the more approachable version. But still a very fun and rewarding challange, I enjoyed the logic. Thank you for setting :)

am 31. Januar 2026, 18:11 Uhr von scarfdoku
That was fun
Thanks for the puzzle

Zuletzt geändert am 31. Januar 2026, 16:41 Uhr

am 31. Januar 2026, 16:15 Uhr von krytolandros
Sorry if I'm being stupid, but how can the parity mirror across the diagonal? If box 1 has 4 evens and 5 odds, wouldn't that imply box 9 has 4 odds and 5 evens?

-The mirror is identical and not the opposite: every cell which is even in box 1 is mirrored as even cell to box 9. Eg. r1c1 has the same parity as r9c9 and so on. ~galium

am 31. Januar 2026, 14:31 Uhr von galium_odoratum
Added solution code

Zuletzt geändert am 31. Januar 2026, 14:32 Uhr

am 31. Januar 2026, 13:20 Uhr von butch02
solution code !!!

-My bad, thank you for pointing this out. ~galium

Schwierigkeit:3
Bewertung:91 %
Gelöst:40 mal
Beobachtet:4 mal
ID:000R3M

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Lösungscode:

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