Logic Masters Deutschland e.V.

Growing Up

(Eingestellt am 22. Dezember 2022, 19:43 Uhr von the_cogito)

Hi all, it's been a bit :)

I recently set a puzzle for Niverio's 25th birthday, and he told me I should post it here. I'm quite happy with this, and I think the ruleset deserves some exploration. Enjoy!

Rules:
Fillomino: Fill the grid with orthogonally connected, non-overlapping regions. Cells in a region each contain a number equal to the size of that region. No two regions of the same size may touch each other orthogonally.

Slitherlink (sort of): Draw a single closed loop through the grid. The loop may not pass through regions, and must contain N total segments along the border of every region, where N is the size of that respective region.


Solve on penpa (answer check for numbers only)

Lösungscode: Row 2, then column 2, no spaces.


Gelöst von kublai, Niverio, Jesper, filuta, Mark Sweep, KNT, ONeill, atomium, Piatato, polar, Agent, filmore, kjholt, bernhard, SudokuExplorer, akodi, misko, ildiko, Xavi 17, RJBlarmo, ascension, jkuo7, widjo, mnasti2, h5663454, tuturitu, sth, GTLSE
Komplette Liste

Kommentare

am 21. August 2023, 03:52 Uhr von mnasti2
I like this one a lot!

am 26. Dezember 2022, 03:16 Uhr von Agent
Very inventive ruleset, some clever and surprising interactions!

am 24. Dezember 2022, 01:29 Uhr von Piatato
Indeed a funny one. Awesome!

am 23. Dezember 2022, 23:30 Uhr von Piatato
What exactly is a line segment in this context?

am 23. Dezember 2022, 14:46 Uhr von ONeill
Great puzzle!

am 23. Dezember 2022, 05:52 Uhr von KNT
super super fun fillomino variant. deserves many more solves

am 23. Dezember 2022, 01:02 Uhr von Mark Sweep
Very interesting combination of puzzle types! The logic felt really fresh.

am 23. Dezember 2022, 00:28 Uhr von filuta
very funny and fun puzzle!

am 23. Dezember 2022, 00:02 Uhr von Jesper
Fun new idea, enjoyed it a lot, thanks!

am 22. Dezember 2022, 21:45 Uhr von Niverio
Thank you so much for this gift! Enjoyed it immensely, and the ruleset is new but intriguing!

Schwierigkeit:4
Bewertung:99 %
Gelöst:28 mal
Beobachtet:2 mal
ID:000CE1

Variantenkombination

Lösung abgeben

Lösungscode:

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